Base | Representation |
---|---|
bin | 110011010010100001… |
… | …0111101101101110001 |
3 | 101112022001212021222222 |
4 | 1212211002331231301 |
5 | 3301033124400423 |
6 | 122333223010425 |
7 | 10646310516332 |
oct | 1464502755561 |
9 | 345261767888 |
10 | 110143200113 |
11 | 42790a68511 |
12 | 1941a899a15 |
13 | a5040879bb |
14 | 548c21c289 |
15 | 2ce99823c8 |
hex | 19a50bdb71 |
110143200113 has 2 divisors, whose sum is σ = 110143200114. Its totient is φ = 110143200112.
The previous prime is 110143200077. The next prime is 110143200143. The reversal of 110143200113 is 311002341011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 62248753009 + 47894447104 = 249497^2 + 218848^2 .
It is a cyclic number.
It is not a de Polignac number, because 110143200113 - 214 = 110143183729 is a prime.
It is a super-2 number, since 2×1101432001132 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 110143200091 and 110143200100.
It is not a weakly prime, because it can be changed into another prime (110143200143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55071600056 + 55071600057.
It is an arithmetic number, because the mean of its divisors is an integer number (55071600057).
Almost surely, 2110143200113 is an apocalyptic number.
It is an amenable number.
110143200113 is a deficient number, since it is larger than the sum of its proper divisors (1).
110143200113 is an equidigital number, since it uses as much as digits as its factorization.
110143200113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 110143200113 its reverse (311002341011), we get a palindrome (421145541124).
The spelling of 110143200113 in words is "one hundred ten billion, one hundred forty-three million, two hundred thousand, one hundred thirteen".
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