Base | Representation |
---|---|
bin | 1010000001001000101011… |
… | …1010000001010010110011 |
3 | 1102222222200021012120111201 |
4 | 2200102022322001102303 |
5 | 2420430423403044103 |
6 | 35232014414352031 |
7 | 2214531500300221 |
oct | 240221272012263 |
9 | 42888607176451 |
10 | 11014626612403 |
11 | 3567305632337 |
12 | 129a8601bb617 |
13 | 61b8a07b88ab |
14 | 2a1179d61b11 |
15 | 1417b081551d |
hex | a048ae814b3 |
11014626612403 has 2 divisors, whose sum is σ = 11014626612404. Its totient is φ = 11014626612402.
The previous prime is 11014626612401. The next prime is 11014626612427. The reversal of 11014626612403 is 30421662641011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11014626612403 - 21 = 11014626612401 is a prime.
Together with 11014626612401, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11014626612401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5507313306201 + 5507313306202.
It is an arithmetic number, because the mean of its divisors is an integer number (5507313306202).
Almost surely, 211014626612403 is an apocalyptic number.
11014626612403 is a deficient number, since it is larger than the sum of its proper divisors (1).
11014626612403 is an equidigital number, since it uses as much as digits as its factorization.
11014626612403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 37.
The spelling of 11014626612403 in words is "eleven trillion, fourteen billion, six hundred twenty-six million, six hundred twelve thousand, four hundred three".
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