Base | Representation |
---|---|
bin | 1010000001011101000111… |
… | …0100100010010111101010 |
3 | 1110000111211111122211021100 |
4 | 2200113101310202113222 |
5 | 2421023141444342100 |
6 | 35234322543022230 |
7 | 2215114426500021 |
oct | 240272164422752 |
9 | 43014744584240 |
10 | 11020111324650 |
11 | 356966a60487a |
12 | 129b930b9a976 |
13 | 61c265ba8c5c |
14 | 2a153a5598b8 |
15 | 1419d20b5400 |
hex | a05d1d225ea |
11020111324650 has 72 divisors (see below), whose sum is σ = 29608930469664. Its totient is φ = 2938541047200.
The previous prime is 11020111324643. The next prime is 11020111324669. The reversal of 11020111324650 is 5642311102011.
11020111324650 is a `hidden beast` number, since 1 + 1 + 0 + 2 + 0 + 1 + 1 + 1 + 3 + 2 + 4 + 650 = 666.
It is an unprimeable number.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 8005645 + ... + 9280655.
It is an arithmetic number, because the mean of its divisors is an integer number (411235145412).
Almost surely, 211020111324650 is an apocalyptic number.
11020111324650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11020111324650 is an abundant number, since it is smaller than the sum of its proper divisors (18588819145014).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11020111324650 is a wasteful number, since it uses less digits than its factorization.
11020111324650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1294236 (or 1294228 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 27.
Adding to 11020111324650 its reverse (5642311102011), we get a palindrome (16662422426661).
The spelling of 11020111324650 in words is "eleven trillion, twenty billion, one hundred eleven million, three hundred twenty-four thousand, six hundred fifty".
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