11020221413 has 2 divisors, whose sum is σ = 11020221414. Its totient is φ = 11020221412.

The previous prime is 11020221391. The next prime is 11020221431. The reversal of 11020221413 is 31412202011.

Together with next prime (11020221431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10807265764 + 212955649 = 103958^2 + 14593^2 .

It is an emirp because it is prime and its reverse (31412202011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11020221413 - 2⁶ = 11020221349 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11020221391 and 11020221400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11020221463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5510110706 + 5510110707.

It is an arithmetic number, because the mean of its divisors is an integer number (5510110707).

Almost surely, 2^11020221413 is an apocalyptic number.

It is an amenable number.

11020221413 is a deficient number, since it is larger than the sum of its proper divisors (1).

11020221413 is an equidigital number, since it uses as much as digits as its factorization.

11020221413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 11020221413 its reverse (31412202011), we get a palindrome (42432423424).

The spelling of 11020221413 in words is "eleven billion, twenty million, two hundred twenty-one thousand, four hundred thirteen".