Base | Representation |
---|---|
bin | 1010000001011101110100… |
… | …1001001111001001101010 |
3 | 1110000112022202010120220122 |
4 | 2200113131021033021222 |
5 | 2421024034113102310 |
6 | 35234353450523242 |
7 | 2215122224324000 |
oct | 240273511171152 |
9 | 43015282116818 |
10 | 11020301300330 |
11 | 3569757870373 |
12 | 129b984736522 |
13 | 61c2963635ba |
14 | 2a155788ca70 |
15 | 1419e3ade555 |
hex | a05dd24f26a |
11020301300330 has 64 divisors (see below), whose sum is σ = 23758210310400. Its totient is φ = 3676270352832.
The previous prime is 11020301300329. The next prime is 11020301300353. The reversal of 11020301300330 is 3300310302011.
It is a junction number, because it is equal to n+sod(n) for n = 11020301300299 and 11020301300308.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 43290872 + ... + 43544691.
It is an arithmetic number, because the mean of its divisors is an integer number (371222036100).
Almost surely, 211020301300330 is an apocalyptic number.
11020301300330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11020301300330 is an abundant number, since it is smaller than the sum of its proper divisors (12737909010070).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11020301300330 is an equidigital number, since it uses as much as digits as its factorization.
11020301300330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 86835628 (or 86835614 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 11020301300330 its reverse (3300310302011), we get a palindrome (14320611602341).
The spelling of 11020301300330 in words is "eleven trillion, twenty billion, three hundred one million, three hundred thousand, three hundred thirty".
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