11020314012433 has 8 divisors (see below), whose sum is σ = 12174339991680. Its totient is φ = 9891651241680.

The previous prime is 11020314012427. The next prime is 11020314012437. The reversal of 11020314012433 is 33421041302011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11020314012433 - 2²⁵ = 11020280458001 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11020314012398 and 11020314012407.

It is not an unprimeable number, because it can be changed into a prime (11020314012437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6340801210 + ... + 6340802947.

It is an arithmetic number, because the mean of its divisors is an integer number (1521792498960).

Almost surely, 2^{11020314012433} is an apocalyptic number.

It is an amenable number.

11020314012433 is a deficient number, since it is larger than the sum of its proper divisors (1154025979247).

11020314012433 is a wasteful number, since it uses less digits than its factorization.

11020314012433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12681604247.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 11020314012433 its reverse (33421041302011), we get a palindrome (44441355314444).

The spelling of 11020314012433 in words is "eleven trillion, twenty billion, three hundred fourteen million, twelve thousand, four hundred thirty-three".