Search a number
-
+
110210011000211 is a prime number
BaseRepresentation
bin11001000011110001000100…
…100011100110110110010011
3112110012222022011021222012002
4121003301010203212312103
5103421140100304001321
61030221440300224215
732133260545542233
oct3103610443466623
9473188264258162
10110210011000211
1132130892049a91
121043b53183b06b
1349659b465c9a5
141d3029b809cc3
15cb1c369b920b
hex643c448e6d93

110210011000211 has 2 divisors, whose sum is σ = 110210011000212. Its totient is φ = 110210011000210.

The previous prime is 110210011000121. The next prime is 110210011000223. The reversal of 110210011000211 is 112000110012011.

Together with previous prime (110210011000121) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 110210011000211 - 218 = 110210010738067 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110210011000192 and 110210011000201.

It is not a weakly prime, because it can be changed into another prime (110210011009211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55105005500105 + 55105005500106.

It is an arithmetic number, because the mean of its divisors is an integer number (55105005500106).

Almost surely, 2110210011000211 is an apocalyptic number.

110210011000211 is a deficient number, since it is larger than the sum of its proper divisors (1).

110210011000211 is an equidigital number, since it uses as much as digits as its factorization.

110210011000211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 110210011000211 its reverse (112000110012011), we get a palindrome (222210121012222).

The spelling of 110210011000211 in words is "one hundred ten trillion, two hundred ten billion, eleven million, two hundred eleven", and thus it is an aban number.