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1102100202103 = 2404214584043
BaseRepresentation
bin10000000010011010010…
…010101000001001110111
310220100201020222002101211
4100002122102220021313
5121024100122431403
62202144200102251
7142424033102515
oct20023222501167
93810636862354
101102100202103
11395441917a0a
12159717164987
137cc09c37104
143b4b03a74b5
151da0505806d
hex1009a4a8277

1102100202103 has 4 divisors (see below), whose sum is σ = 1102105026568. Its totient is φ = 1102095377640.

The previous prime is 1102100202097. The next prime is 1102100202109. The reversal of 1102100202103 is 3012020012011.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1102100202097) and next prime (1102100202109).

It is a cyclic number.

It is not a de Polignac number, because 1102100202103 - 229 = 1101563331191 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1102100202109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2051601 + ... + 2532442.

It is an arithmetic number, because the mean of its divisors is an integer number (275526256642).

Almost surely, 21102100202103 is an apocalyptic number.

1102100202103 is a deficient number, since it is larger than the sum of its proper divisors (4824465).

1102100202103 is an equidigital number, since it uses as much as digits as its factorization.

1102100202103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4824464.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 1102100202103 its reverse (3012020012011), we get a palindrome (4114120214114).

The spelling of 1102100202103 in words is "one trillion, one hundred two billion, one hundred million, two hundred two thousand, one hundred three".

Divisors: 1 240421 4584043 1102100202103