Search a number
-
+
1102100231411 is a prime number
BaseRepresentation
bin10000000010011010010…
…010101111010011110011
310220100201021000120121022
4100002122102233103303
5121024100124401121
62202144200450055
7142424033254124
oct20023222572363
93810637016538
101102100231411
11395441937a33
1215971717992b
137cc09c4755a
143b4b03b404b
151da05061aab
hex1009a4af4f3

1102100231411 has 2 divisors, whose sum is σ = 1102100231412. Its totient is φ = 1102100231410.

The previous prime is 1102100231389. The next prime is 1102100231413. The reversal of 1102100231411 is 1141320012011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1102100231411 - 230 = 1101026489587 is a prime.

It is a Sophie Germain prime.

Together with 1102100231413, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1102100231411.

It is not a weakly prime, because it can be changed into another prime (1102100231413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551050115705 + 551050115706.

It is an arithmetic number, because the mean of its divisors is an integer number (551050115706).

Almost surely, 21102100231411 is an apocalyptic number.

1102100231411 is a deficient number, since it is larger than the sum of its proper divisors (1).

1102100231411 is an equidigital number, since it uses as much as digits as its factorization.

1102100231411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 1102100231411 its reverse (1141320012011), we get a palindrome (2243420243422).

The spelling of 1102100231411 in words is "one trillion, one hundred two billion, one hundred million, two hundred thirty-one thousand, four hundred eleven".