Base | Representation |
---|---|
bin | 110011010100100100… |
… | …1011010100100110011 |
3 | 101112110212022200202211 |
4 | 1212221021122210303 |
5 | 3301203233000201 |
6 | 122344121352551 |
7 | 10651104354256 |
oct | 1465111324463 |
9 | 345425280684 |
10 | 110212000051 |
11 | 4281688996a |
12 | 19439938757 |
13 | a5153c621a |
14 | 549740b09d |
15 | 2d00a22651 |
hex | 19a925a933 |
110212000051 has 8 divisors (see below), whose sum is σ = 110768500224. Its totient is φ = 109656873480.
The previous prime is 110212000049. The next prime is 110212000057. The reversal of 110212000051 is 150000212011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 110212000051 - 21 = 110212000049 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 110211999995 and 110212000040.
It is not an unprimeable number, because it can be changed into a prime (110212000057) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 182335 + ... + 503656.
It is an arithmetic number, because the mean of its divisors is an integer number (13846062528).
Almost surely, 2110212000051 is an apocalyptic number.
110212000051 is a deficient number, since it is larger than the sum of its proper divisors (556500173).
110212000051 is an equidigital number, since it uses as much as digits as its factorization.
110212000051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 686801.
The product of its (nonzero) digits is 20, while the sum is 13.
Adding to 110212000051 its reverse (150000212011), we get a palindrome (260212212062).
The spelling of 110212000051 in words is "one hundred ten billion, two hundred twelve million, fifty-one", and thus it is an aban number.
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