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110212000051 = 347463685991
BaseRepresentation
bin110011010100100100…
…1011010100100110011
3101112110212022200202211
41212221021122210303
53301203233000201
6122344121352551
710651104354256
oct1465111324463
9345425280684
10110212000051
114281688996a
1219439938757
13a5153c621a
14549740b09d
152d00a22651
hex19a925a933

110212000051 has 8 divisors (see below), whose sum is σ = 110768500224. Its totient is φ = 109656873480.

The previous prime is 110212000049. The next prime is 110212000057. The reversal of 110212000051 is 150000212011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 110212000051 - 21 = 110212000049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110211999995 and 110212000040.

It is not an unprimeable number, because it can be changed into a prime (110212000057) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 182335 + ... + 503656.

It is an arithmetic number, because the mean of its divisors is an integer number (13846062528).

Almost surely, 2110212000051 is an apocalyptic number.

110212000051 is a deficient number, since it is larger than the sum of its proper divisors (556500173).

110212000051 is an equidigital number, since it uses as much as digits as its factorization.

110212000051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 686801.

The product of its (nonzero) digits is 20, while the sum is 13.

Adding to 110212000051 its reverse (150000212011), we get a palindrome (260212212062).

The spelling of 110212000051 in words is "one hundred ten billion, two hundred twelve million, fifty-one", and thus it is an aban number.

Divisors: 1 347 463 160661 685991 238038877 317613833 110212000051