Base | Representation |
---|---|
bin | 10000000010011011100… |
… | …001111101110001010111 |
3 | 10220100202201002201210011 |
4 | 100002123201331301113 |
5 | 121024120434000043 |
6 | 2202150221541051 |
7 | 142424404634041 |
oct | 20023341756127 |
9 | 3810681081704 |
10 | 1102121000023 |
11 | 39545263277a |
12 | 159722114787 |
13 | 7cc11339784 |
14 | 3b4b305ca91 |
15 | 1da06cb559d |
hex | 1009b87dc57 |
1102121000023 has 2 divisors, whose sum is σ = 1102121000024. Its totient is φ = 1102121000022.
The previous prime is 1102120999963. The next prime is 1102121000053. The reversal of 1102121000023 is 3200001212011.
It is a strong prime.
It is an emirp because it is prime and its reverse (3200001212011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1102121000023 - 229 = 1101584129111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1102120999967 and 1102121000012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1102121000053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551060500011 + 551060500012.
It is an arithmetic number, because the mean of its divisors is an integer number (551060500012).
Almost surely, 21102121000023 is an apocalyptic number.
1102121000023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1102121000023 is an equidigital number, since it uses as much as digits as its factorization.
1102121000023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 1102121000023 its reverse (3200001212011), we get a palindrome (4302122212034).
The spelling of 1102121000023 in words is "one trillion, one hundred two billion, one hundred twenty-one million, twenty-three", and thus it is an aban number.
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