Base | Representation |
---|---|
bin | 110011010100100110… |
… | …1101001110110100111 |
3 | 101112110221102010222202 |
4 | 1212221031221312213 |
5 | 3301204024024312 |
6 | 122344201245115 |
7 | 10651116662633 |
oct | 1465115516647 |
9 | 345427363882 |
10 | 110213111207 |
11 | 42817478781 |
12 | 1943a19379b |
13 | a5156c4c04 |
14 | 5497619dc3 |
15 | 2d00b919c2 |
hex | 19a9369da7 |
110213111207 has 2 divisors, whose sum is σ = 110213111208. Its totient is φ = 110213111206.
The previous prime is 110213111191. The next prime is 110213111227. The reversal of 110213111207 is 702111312011.
It is an a-pointer prime, because the next prime (110213111227) can be obtained adding 110213111207 to its sum of digits (20).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110213111207 - 24 = 110213111191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110213111227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55106555603 + 55106555604.
It is an arithmetic number, because the mean of its divisors is an integer number (55106555604).
Almost surely, 2110213111207 is an apocalyptic number.
110213111207 is a deficient number, since it is larger than the sum of its proper divisors (1).
110213111207 is an equidigital number, since it uses as much as digits as its factorization.
110213111207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 20.
Adding to 110213111207 its reverse (702111312011), we get a palindrome (812324423218).
The spelling of 110213111207 in words is "one hundred ten billion, two hundred thirteen million, one hundred eleven thousand, two hundred seven".
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