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110213141 is a prime number
BaseRepresentation
bin1101001000110…
…11100000010101
321200101102000012
412210123200111
5211203310031
614534130005
72505540053
oct644334025
9250342005
10110213141
1157237845
1230ab0905
1319aab39c
14108cd1d3
159a20b2b
hex691b815

110213141 has 2 divisors, whose sum is σ = 110213142. Its totient is φ = 110213140.

The previous prime is 110213123. The next prime is 110213143. The reversal of 110213141 is 141312011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98585041 + 11628100 = 9929^2 + 3410^2 .

It is a cyclic number.

It is not a de Polignac number, because 110213141 - 210 = 110212117 is a prime.

Together with 110213143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110213143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55106570 + 55106571.

It is an arithmetic number, because the mean of its divisors is an integer number (55106571).

Almost surely, 2110213141 is an apocalyptic number.

It is an amenable number.

110213141 is a deficient number, since it is larger than the sum of its proper divisors (1).

110213141 is an equidigital number, since it uses as much as digits as its factorization.

110213141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 110213141 is about 10498.2446627996. The cubic root of 110213141 is about 479.4512551376.

Adding to 110213141 its reverse (141312011), we get a palindrome (251525152).

The spelling of 110213141 in words is "one hundred ten million, two hundred thirteen thousand, one hundred forty-one".