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11021325133 = 713121113463
BaseRepresentation
bin10100100001110110…
…00001001101001101
31001110002120022211011
422100323001031031
5140032424401013
65021345125221
7540055501150
oct122073011515
931402508734
1011021325133
114746283775
122177029811
131068482c80
14767a61c97
154478a2c3d
hex290ec134d

11021325133 has 8 divisors (see below), whose sum is σ = 13564707968. Its totient is φ = 8720169264.

The previous prime is 11021325083. The next prime is 11021325149. The reversal of 11021325133 is 33152312011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11021325133 - 213 = 11021316941 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11021326133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60556641 + ... + 60556822.

It is an arithmetic number, because the mean of its divisors is an integer number (1695588496).

Almost surely, 211021325133 is an apocalyptic number.

11021325133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11021325133 is a deficient number, since it is larger than the sum of its proper divisors (2543382835).

11021325133 is a wasteful number, since it uses less digits than its factorization.

11021325133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121113483.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 11021325133 its reverse (33152312011), we get a palindrome (44173637144).

The spelling of 11021325133 in words is "eleven billion, twenty-one million, three hundred twenty-five thousand, one hundred thirty-three".

Divisors: 1 7 13 91 121113463 847794241 1574475019 11021325133