Base | Representation |
---|---|
bin | 1010000001100010000001… |
… | …1010111011010110101111 |
3 | 1110000122020102000001022001 |
4 | 2200120200122323112233 |
5 | 2421033342040330221 |
6 | 35235101451033131 |
7 | 2215162211236366 |
oct | 240304032732657 |
9 | 43018212001261 |
10 | 11021430011311 |
11 | 356a186a05665 |
12 | 12a003a73b7a7 |
13 | 61c416157615 |
14 | 2a16237427dd |
15 | 141a5cc47391 |
hex | a06206bb5af |
11021430011311 has 4 divisors (see below), whose sum is σ = 11035989364792. Its totient is φ = 11006870657832.
The previous prime is 11021430011227. The next prime is 11021430011321. The reversal of 11021430011311 is 11311003412011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11021430011311 - 217 = 11021429880239 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11021430011321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7279675605 + ... + 7279677118.
It is an arithmetic number, because the mean of its divisors is an integer number (2758997341198).
Almost surely, 211021430011311 is an apocalyptic number.
11021430011311 is a deficient number, since it is larger than the sum of its proper divisors (14559353481).
11021430011311 is an equidigital number, since it uses as much as digits as its factorization.
11021430011311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14559353480.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 11021430011311 its reverse (11311003412011), we get a palindrome (22332433423322).
The spelling of 11021430011311 in words is "eleven trillion, twenty-one billion, four hundred thirty million, eleven thousand, three hundred eleven".
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