Base | Representation |
---|---|
bin | 11001000011111010010111… |
… | …111101011000101001010101 |
3 | 112110020221002022201221222211 |
4 | 121003322113331120221111 |
5 | 103421321030022420201 |
6 | 1030230211415353421 |
7 | 32134063232416414 |
oct | 3103722775305125 |
9 | 473227068657884 |
10 | 110220000201301 |
11 | 32135048758681 |
12 | 1044145b082871 |
13 | 4966917038a73 |
14 | 1d3096835b47b |
15 | cb211d942651 |
hex | 643e97f58a55 |
110220000201301 has 2 divisors, whose sum is σ = 110220000201302. Its totient is φ = 110220000201300.
The previous prime is 110220000201083. The next prime is 110220000201313. The reversal of 110220000201301 is 103102000022011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 87270161422500 + 22949838778801 = 9341850^2 + 4790599^2 .
It is a cyclic number.
It is not a de Polignac number, because 110220000201301 - 231 = 110217852717653 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110220001201301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55110000100650 + 55110000100651.
It is an arithmetic number, because the mean of its divisors is an integer number (55110000100651).
Almost surely, 2110220000201301 is an apocalyptic number.
It is an amenable number.
110220000201301 is a deficient number, since it is larger than the sum of its proper divisors (1).
110220000201301 is an equidigital number, since it uses as much as digits as its factorization.
110220000201301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 110220000201301 its reverse (103102000022011), we get a palindrome (213322000223312).
The spelling of 110220000201301 in words is "one hundred ten trillion, two hundred twenty billion, two hundred one thousand, three hundred one".
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