1102204440133 has 4 divisors (see below), whose sum is σ = 1160215200160. Its totient is φ = 1044193680108.

The previous prime is 1102204440121. The next prime is 1102204440173. The reversal of 1102204440133 is 3310444022011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1102204440133 - 2⁹ = 1102204439621 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1102204440098 and 1102204440107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1102204440173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29005379985 + ... + 29005380022.

It is an arithmetic number, because the mean of its divisors is an integer number (290053800040).

Almost surely, 2^{1102204440133} is an apocalyptic number.

It is an amenable number.

1102204440133 is a deficient number, since it is larger than the sum of its proper divisors (58010760027).

1102204440133 is an equidigital number, since it uses as much as digits as its factorization.

1102204440133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58010760026.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1102204440133 its reverse (3310444022011), we get a palindrome (4412648462144).

The spelling of 1102204440133 in words is "one trillion, one hundred two billion, two hundred four million, four hundred forty thousand, one hundred thirty-three".