Base | Representation |
---|---|
bin | 1010000001100111111011… |
… | …0010011001001110110111 |
3 | 1110000210022202002110010011 |
4 | 2200121332302121032313 |
5 | 2421100112341040203 |
6 | 35235522524441051 |
7 | 2215246354300066 |
oct | 240317662311667 |
9 | 43023282073104 |
10 | 11023013221303 |
11 | 356a919659776 |
12 | 12a04009a9187 |
13 | 61c609162075 |
14 | 2a1733b061dd |
15 | 141b01c2b76d |
hex | a067ec993b7 |
11023013221303 has 2 divisors, whose sum is σ = 11023013221304. Its totient is φ = 11023013221302.
The previous prime is 11023013221301. The next prime is 11023013221321. The reversal of 11023013221303 is 30312231032011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11023013221303 - 21 = 11023013221301 is a prime.
Together with 11023013221301, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11023013221301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511506610651 + 5511506610652.
It is an arithmetic number, because the mean of its divisors is an integer number (5511506610652).
Almost surely, 211023013221303 is an apocalyptic number.
11023013221303 is a deficient number, since it is larger than the sum of its proper divisors (1).
11023013221303 is an equidigital number, since it uses as much as digits as its factorization.
11023013221303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 11023013221303 its reverse (30312231032011), we get a palindrome (41335244253314).
The spelling of 11023013221303 in words is "eleven trillion, twenty-three billion, thirteen million, two hundred twenty-one thousand, three hundred three".
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