11023031002013 has 2 divisors, whose sum is σ = 11023031002014. Its totient is φ = 11023031002012.

The previous prime is 11023031001991. The next prime is 11023031002033. The reversal of 11023031002013 is 31020013032011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6576444833764 + 4446586168249 = 2564458^2 + 2108693^2 .

It is an emirp because it is prime and its reverse (31020013032011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11023031002013 - 2³² = 11018736034717 is a prime.

It is a super-3 number, since 3×11023031002013³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11023031001982 and 11023031002000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11023031002033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511515501006 + 5511515501007.

It is an arithmetic number, because the mean of its divisors is an integer number (5511515501007).

Almost surely, 2^{11023031002013} is an apocalyptic number.

It is an amenable number.

11023031002013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11023031002013 is an equidigital number, since it uses as much as digits as its factorization.

11023031002013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 11023031002013 its reverse (31020013032011), we get a palindrome (42043044034024).

The spelling of 11023031002013 in words is "eleven trillion, twenty-three billion, thirty-one million, two thousand, thirteen".