Base | Representation |
---|---|
bin | 10100100010000100… |
… | …01101111001010001 |
3 | 1001110020010012021022 |
4 | 22101002031321101 |
5 | 140033420241423 |
6 | 5021453405225 |
7 | 540110520434 |
oct | 122102157121 |
9 | 31406105238 |
10 | 11023212113 |
11 | 4747352461 |
12 | 2177799815 |
13 | 1068993b24 |
14 | 767dd381b |
15 | 447b26dc8 |
hex | 29108de51 |
11023212113 has 2 divisors, whose sum is σ = 11023212114. Its totient is φ = 11023212112.
The previous prime is 11023212091. The next prime is 11023212143. The reversal of 11023212113 is 31121232011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9720579649 + 1302632464 = 98593^2 + 36092^2 .
It is a cyclic number.
It is not a de Polignac number, because 11023212113 - 216 = 11023146577 is a prime.
It is a super-2 number, since 2×110232121132 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11023212091 and 11023212100.
It is not a weakly prime, because it can be changed into another prime (11023212143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5511606056 + 5511606057.
It is an arithmetic number, because the mean of its divisors is an integer number (5511606057).
Almost surely, 211023212113 is an apocalyptic number.
It is an amenable number.
11023212113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11023212113 is an equidigital number, since it uses as much as digits as its factorization.
11023212113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 11023212113 its reverse (31121232011), we get a palindrome (42144444124).
The spelling of 11023212113 in words is "eleven billion, twenty-three million, two hundred twelve thousand, one hundred thirteen".
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