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110232144031 is a prime number
BaseRepresentation
bin110011010101001011…
…0010000100010011111
3101112112021020010010011
41212222112100202133
53301223412102111
6122350121224051
710651440523132
oct1465226204237
9345467203104
10110232144031
1142827198389
1219444632027
13a51962a039
145499d72219
152d026a1021
hex19aa59089f

110232144031 has 2 divisors, whose sum is σ = 110232144032. Its totient is φ = 110232144030.

The previous prime is 110232144007. The next prime is 110232144041. The reversal of 110232144031 is 130441232011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 110232144031 - 211 = 110232141983 is a prime.

It is a super-3 number, since 3×1102321440313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 110232143993 and 110232144011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110232144041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55116072015 + 55116072016.

It is an arithmetic number, because the mean of its divisors is an integer number (55116072016).

Almost surely, 2110232144031 is an apocalyptic number.

110232144031 is a deficient number, since it is larger than the sum of its proper divisors (1).

110232144031 is an equidigital number, since it uses as much as digits as its factorization.

110232144031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 110232144031 its reverse (130441232011), we get a palindrome (240673376042).

The spelling of 110232144031 in words is "one hundred ten billion, two hundred thirty-two million, one hundred forty-four thousand, thirty-one".