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130441232011 = 373525438703
BaseRepresentation
bin111100101111011100…
…1110011111010001011
3110110200200012011011011
41321132321303322023
54114120423411021
6135531320144351
712265312115026
oct1713671637213
9413620164134
10130441232011
1150357747292
12213446080b7
13c3ba42166c
146455d241bd
1535d696dde1
hex1e5ee73e8b

130441232011 has 4 divisors (see below), whose sum is σ = 133966670752. Its totient is φ = 126915793272.

The previous prime is 130441231969. The next prime is 130441232017. The reversal of 130441232011 is 110232144031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130441232011 - 215 = 130441199243 is a prime.

It is a super-2 number, since 2×1304412320112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130441232017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1762719315 + ... + 1762719388.

It is an arithmetic number, because the mean of its divisors is an integer number (33491667688).

Almost surely, 2130441232011 is an apocalyptic number.

130441232011 is a deficient number, since it is larger than the sum of its proper divisors (3525438741).

130441232011 is an equidigital number, since it uses as much as digits as its factorization.

130441232011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3525438740.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 130441232011 its reverse (110232144031), we get a palindrome (240673376042).

The spelling of 130441232011 in words is "one hundred thirty billion, four hundred forty-one million, two hundred thirty-two thousand, eleven".

Divisors: 1 37 3525438703 130441232011