110233121433341 has 4 divisors (see below), whose sum is σ = 113789028576384. Its totient is φ = 106677214290300.

The previous prime is 110233121433257. The next prime is 110233121433373. The reversal of 110233121433341 is 143334121332011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110233121433341 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110233121433298 and 110233121433307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110233121433041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1777953571475 + ... + 1777953571536.

It is an arithmetic number, because the mean of its divisors is an integer number (28447257144096).

Almost surely, 2^{110233121433341} is an apocalyptic number.

It is an amenable number.

110233121433341 is a deficient number, since it is larger than the sum of its proper divisors (3555907143043).

110233121433341 is an equidigital number, since it uses as much as digits as its factorization.

110233121433341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3555907143042.

The product of its (nonzero) digits is 15552, while the sum is 32.

Adding to 110233121433341 its reverse (143334121332011), we get a palindrome (253567242765352).

The spelling of 110233121433341 in words is "one hundred ten trillion, two hundred thirty-three billion, one hundred twenty-one million, four hundred thirty-three thousand, three hundred forty-one".