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1102341210043 is a prime number
BaseRepresentation
bin10000000010101000101…
…001111111111110111011
310220101100001110120010211
4100002220221333332323
5121030043322210133
62202224125451551
7142433020453543
oct20025051777673
93811301416124
101102341210043
11395555969827
12159783a10bb7
137cc47b4b968
143b4d43c2323
151da1b2b2bcd
hex100a8a7ffbb

1102341210043 has 2 divisors, whose sum is σ = 1102341210044. Its totient is φ = 1102341210042.

The previous prime is 1102341210041. The next prime is 1102341210073. The reversal of 1102341210043 is 3400121432011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1102341210043 - 21 = 1102341210041 is a prime.

It is a super-2 number, since 2×11023412100432 (a number of 25 digits) contains 22 as substring.

Together with 1102341210041, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1102341209996 and 1102341210023.

It is not a weakly prime, because it can be changed into another prime (1102341210041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551170605021 + 551170605022.

It is an arithmetic number, because the mean of its divisors is an integer number (551170605022).

Almost surely, 21102341210043 is an apocalyptic number.

1102341210043 is a deficient number, since it is larger than the sum of its proper divisors (1).

1102341210043 is an equidigital number, since it uses as much as digits as its factorization.

1102341210043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 1102341210043 its reverse (3400121432011), we get a palindrome (4502462642054).

The spelling of 1102341210043 in words is "one trillion, one hundred two billion, three hundred forty-one million, two hundred ten thousand, forty-three".