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11024044313 = 83132819811
BaseRepresentation
bin10100100010001010…
…11001000100011001
31001110021200110211112
422101011121010121
5140034123404223
65021523310105
7540120554612
oct122105310431
931407613745
1011024044313
114747870727
122177b1b335
131068bc5859
1476816cc09
15447c3d778
hex291159119

11024044313 has 4 divisors (see below), whose sum is σ = 11156864208. Its totient is φ = 10891224420.

The previous prime is 11024044303. The next prime is 11024044319. The reversal of 11024044313 is 31344042011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11024044313 - 26 = 11024044249 is a prime.

It is a super-3 number, since 3×110240443133 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11024044319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66409823 + ... + 66409988.

It is an arithmetic number, because the mean of its divisors is an integer number (2789216052).

Almost surely, 211024044313 is an apocalyptic number.

It is an amenable number.

11024044313 is a deficient number, since it is larger than the sum of its proper divisors (132819895).

11024044313 is an equidigital number, since it uses as much as digits as its factorization.

11024044313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 132819894.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 11024044313 its reverse (31344042011), we get a palindrome (42368086324).

The spelling of 11024044313 in words is "eleven billion, twenty-four million, forty-four thousand, three hundred thirteen".

Divisors: 1 83 132819811 11024044313