11024314000034 has 4 divisors (see below), whose sum is σ = 16536471000054. Its totient is φ = 5512157000016.

The previous prime is 11024314000019. The next prime is 11024314000039. The reversal of 11024314000034 is 43000041342011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 6570327460225 + 4453986539809 = 2563265^2 + 2110447^2 .

It is a junction number, because it is equal to n+sod(n) for n = 11024313999973 and 11024314000009.

It is not an unprimeable number, because it can be changed into a prime (11024314000039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2756078500007 + ... + 2756078500010.

Almost surely, 2^{11024314000034} is an apocalyptic number.

11024314000034 is a deficient number, since it is larger than the sum of its proper divisors (5512157000020).

11024314000034 is an equidigital number, since it uses as much as digits as its factorization.

11024314000034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5512157000019.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 11024314000034 its reverse (43000041342011), we get a palindrome (54024355342045).

The spelling of 11024314000034 in words is "eleven trillion, twenty-four billion, three hundred fourteen million, thirty-four", and thus it is an aban number.