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11031382513 is a prime number
BaseRepresentation
bin10100100011000010…
…11000100111110001
31001110210111021221201
422101201120213301
5140043013220023
65022344451201
7540240130024
oct122141304761
931423437851
1011031382513
114750a22a58
12217a479b01
13106a594998
1476911d1bb
154486dcbad
hex2918589f1

11031382513 has 2 divisors, whose sum is σ = 11031382514. Its totient is φ = 11031382512.

The previous prime is 11031382511. The next prime is 11031382553. The reversal of 11031382513 is 31528313011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9673312609 + 1358069904 = 98353^2 + 36852^2 .

It is a cyclic number.

It is not a de Polignac number, because 11031382513 - 21 = 11031382511 is a prime.

Together with 11031382511, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11031382511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5515691256 + 5515691257.

It is an arithmetic number, because the mean of its divisors is an integer number (5515691257).

Almost surely, 211031382513 is an apocalyptic number.

It is an amenable number.

11031382513 is a deficient number, since it is larger than the sum of its proper divisors (1).

11031382513 is an equidigital number, since it uses as much as digits as its factorization.

11031382513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 28.

Adding to 11031382513 its reverse (31528313011), we get a palindrome (42559695524).

It can be divided in two parts, 1103 and 1382513, that added together give a triangular number (1383616 = T1663).

The spelling of 11031382513 in words is "eleven billion, thirty-one million, three hundred eighty-two thousand, five hundred thirteen".