110320130101211 has 2 divisors, whose sum is σ = 110320130101212. Its totient is φ = 110320130101210.

The previous prime is 110320130101199. The next prime is 110320130101213. The reversal of 110320130101211 is 112101031023011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110320130101211 is a prime.

It is a super-2 number, since 2×110320130101211² (a number of 29 digits) contains 22 as substring.

Together with 110320130101213, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 110320130101211.

It is not a weakly prime, because it can be changed into another prime (110320130101213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55160065050605 + 55160065050606.

It is an arithmetic number, because the mean of its divisors is an integer number (55160065050606).

Almost surely, 2^{110320130101211} is an apocalyptic number.

110320130101211 is a deficient number, since it is larger than the sum of its proper divisors (1).

110320130101211 is an equidigital number, since it uses as much as digits as its factorization.

110320130101211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 110320130101211 its reverse (112101031023011), we get a palindrome (222421161124222).

The spelling of 110320130101211 in words is "one hundred ten trillion, three hundred twenty billion, one hundred thirty million, one hundred one thousand, two hundred eleven".