11032220013 has 4 divisors (see below), whose sum is σ = 14709626688. Its totient is φ = 7354813340.

The previous prime is 11032220011. The next prime is 11032220041. The reversal of 11032220013 is 31002223011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31002223011 = 3 ⋅10334074337.

It is a cyclic number.

It is not a de Polignac number, because 11032220013 - 2¹ = 11032220011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11032219974 and 11032220001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11032220011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1838703333 + ... + 1838703338.

It is an arithmetic number, because the mean of its divisors is an integer number (3677406672).

Almost surely, 2^11032220013 is an apocalyptic number.

It is an amenable number.

11032220013 is a deficient number, since it is larger than the sum of its proper divisors (3677406675).

11032220013 is an equidigital number, since it uses as much as digits as its factorization.

11032220013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3677406674.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 11032220013 its reverse (31002223011), we get a palindrome (42034443024).

The spelling of 11032220013 in words is "eleven billion, thirty-two million, two hundred twenty thousand, thirteen".