Base | Representation |
---|---|
bin | 110011010111111001… |
… | …0100010100110100111 |
3 | 101112202122000122022111 |
4 | 1212233302202212213 |
5 | 3301420300203020 |
6 | 122403142141451 |
7 | 10653626542162 |
oct | 1465762424647 |
9 | 345678018274 |
10 | 110323444135 |
11 | 42873787513 |
12 | 1946b121887 |
13 | a532515978 |
14 | 54a813aad9 |
15 | 2d0a6d7d5a |
hex | 19afca29a7 |
110323444135 has 4 divisors (see below), whose sum is σ = 132388132968. Its totient is φ = 88258755304.
The previous prime is 110323444081. The next prime is 110323444139. The reversal of 110323444135 is 531444323011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 110323444135 - 233 = 101733509543 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 110323444097 and 110323444106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110323444139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11032344409 + ... + 11032344418.
It is an arithmetic number, because the mean of its divisors is an integer number (33097033242).
Almost surely, 2110323444135 is an apocalyptic number.
110323444135 is a deficient number, since it is larger than the sum of its proper divisors (22064688833).
110323444135 is an equidigital number, since it uses as much as digits as its factorization.
110323444135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22064688832.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 110323444135 its reverse (531444323011), we get a palindrome (641767767146).
The spelling of 110323444135 in words is "one hundred ten billion, three hundred twenty-three million, four hundred forty-four thousand, one hundred thirty-five".
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