11033000115 has 16 divisors (see below), whose sum is σ = 17657385216. Its totient is φ = 5882738400.

The previous prime is 11033000053. The next prime is 11033000117. The reversal of 11033000115 is 51100033011.

11033000115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11033000115 - 2⁷ = 11032999987 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a junction number, because it is equal to n+sod(n) for n = 11033000094 and 11033000103.

It is not an unprimeable number, because it can be changed into a prime (11033000117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34591 + ... + 152520.

It is an arithmetic number, because the mean of its divisors is an integer number (1103586576).

Almost surely, 2^11033000115 is an apocalyptic number.

11033000115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

11033000115 is a deficient number, since it is larger than the sum of its proper divisors (6624385101).

11033000115 is a wasteful number, since it uses less digits than its factorization.

11033000115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 191050.

The product of its (nonzero) digits is 45, while the sum is 15.

Adding to 11033000115 its reverse (51100033011), we get a palindrome (62133033126).

The spelling of 11033000115 in words is "eleven billion, thirty-three million, one hundred fifteen", and thus it is an aban number.