11033010103121 has 2 divisors, whose sum is σ = 11033010103122. Its totient is φ = 11033010103120.

The previous prime is 11033010103079. The next prime is 11033010103123. The reversal of 11033010103121 is 12130101033011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5656691424400 + 5376318678721 = 2378380^2 + 2318689^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11033010103121 is a prime.

Together with 11033010103123, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11033010103121.

It is not a weakly prime, because it can be changed into another prime (11033010103123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5516505051560 + 5516505051561.

It is an arithmetic number, because the mean of its divisors is an integer number (5516505051561).

Almost surely, 2^{11033010103121} is an apocalyptic number.

It is an amenable number.

11033010103121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11033010103121 is an equidigital number, since it uses as much as digits as its factorization.

11033010103121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11033010103121 its reverse (12130101033011), we get a palindrome (23163111136132).

The spelling of 11033010103121 in words is "eleven trillion, thirty-three billion, ten million, one hundred three thousand, one hundred twenty-one".