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110330113130 = 2511033011313
BaseRepresentation
bin110011011000000101…
…1111110110001101010
3101112210002120110110022
41212300023332301222
53301424002110010
6122403541120442
710654040326256
oct1466013766152
9345702513408
10110330113130
1142877521a86
12194713b9122
13a533a0c313
1454a8d95266
152d0b0a3d55
hex19b02fec6a

110330113130 has 8 divisors (see below), whose sum is σ = 198594203652. Its totient is φ = 44132045248.

The previous prime is 110330113073. The next prime is 110330113139. The reversal of 110330113130 is 31311033011.

It can be written as a sum of positive squares in 2 ways, for example, as 101533361449 + 8796751681 = 318643^2 + 93791^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 110330113099 and 110330113108.

It is not an unprimeable number, because it can be changed into a prime (110330113139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5516505647 + ... + 5516505666.

Almost surely, 2110330113130 is an apocalyptic number.

110330113130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

110330113130 is a deficient number, since it is larger than the sum of its proper divisors (88264090522).

110330113130 is a wasteful number, since it uses less digits than its factorization.

110330113130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11033011320.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 110330113130 its reverse (31311033011), we get a palindrome (141641146141).

The spelling of 110330113130 in words is "one hundred ten billion, three hundred thirty million, one hundred thirteen thousand, one hundred thirty".

Divisors: 1 2 5 10 11033011313 22066022626 55165056565 110330113130