| Base | Representation |
|---|---|
| bin | 10100100011010000… |
| … | …00100000001000000 |
| 3 | 1001110220210020100000 |
| 4 | 22101220010001000 |
| 5 | 140043440224440 |
| 6 | 5022450200000 |
| 7 | 540261040602 |
| oct | 122150040100 |
| 9 | 31426706300 |
| 10 | 11033133120 |
| 11 | 4751a09239 |
| 12 | 217ab83000 |
| 13 | 106aa58749 |
| 14 | 769457172 |
| 15 | 448936730 |
| hex | 291a04040 |
11033133120 has 672 divisors, whose sum is σ = 42603724800. Its totient is φ = 2709780480.
The previous prime is 11033133073. The next prime is 11033133121. The reversal of 11033133120 is 2133133011.
It is a happy number.
11033133120 is a `hidden beast` number, since 1 + 1 + 0 + 331 + 331 + 2 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 11033133093 and 11033133102.
It is not an unprimeable number, because it can be changed into a prime (11033133121) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 55442781 + ... + 55442979.
It is an arithmetic number, because the mean of its divisors is an integer number (63398400).
Almost surely, 211033133120 is an apocalyptic number.
11033133120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11033133120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21301862400).
11033133120 is an abundant number, since it is smaller than the sum of its proper divisors (31570591680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11033133120 is a wasteful number, since it uses less digits than its factorization.
11033133120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 285 (or 263 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 18.
Adding to 11033133120 its reverse (2133133011), we get a palindrome (13166266131).
It can be divided in two parts, 11033133 and 120, that added together give a triangular number (11033253 = T4697).
The spelling of 11033133120 in words is "eleven billion, thirty-three million, one hundred thirty-three thousand, one hundred twenty".
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