Base | Representation |
---|---|
bin | 10100100011010000… |
… | …00101111110010111 |
3 | 1001110220210122100011 |
4 | 22101220011332113 |
5 | 140043441004033 |
6 | 5022450301051 |
7 | 540261103153 |
oct | 122150057627 |
9 | 31426718304 |
10 | 11033141143 |
11 | 4751a14272 |
12 | 217ab87787 |
13 | 106aa5c2ab |
14 | 76945a063 |
15 | 448938ccd |
hex | 291a05f97 |
11033141143 has 2 divisors, whose sum is σ = 11033141144. Its totient is φ = 11033141142.
The previous prime is 11033141099. The next prime is 11033141159. The reversal of 11033141143 is 34114133011.
11033141143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11033141143 - 225 = 10999586711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11033141173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5516570571 + 5516570572.
It is an arithmetic number, because the mean of its divisors is an integer number (5516570572).
Almost surely, 211033141143 is an apocalyptic number.
11033141143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11033141143 is an equidigital number, since it uses as much as digits as its factorization.
11033141143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 11033141143 its reverse (34114133011), we get a palindrome (45147274154).
The spelling of 11033141143 in words is "eleven billion, thirty-three million, one hundred forty-one thousand, one hundred forty-three".
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