Base | Representation |
---|---|
bin | 10000000011100011100… |
… | …101111110010011000111 |
3 | 10220110212222001211002222 |
4 | 100003203211332103013 |
5 | 121034104440312221 |
6 | 2202510211122555 |
7 | 142466355230264 |
oct | 20034345762307 |
9 | 3813788054088 |
10 | 1103330010311 |
11 | 395a13033031 |
12 | 1599baba345b |
13 | 80074967189 |
14 | 3b58985626b |
15 | 1da77ed09ab |
hex | 100e397e4c7 |
1103330010311 has 2 divisors, whose sum is σ = 1103330010312. Its totient is φ = 1103330010310.
The previous prime is 1103330010301. The next prime is 1103330010331. The reversal of 1103330010311 is 1130100333011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1103330010311 - 218 = 1103329748167 is a prime.
It is a super-2 number, since 2×11033300103112 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1103330010311.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1103330010301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551665005155 + 551665005156.
It is an arithmetic number, because the mean of its divisors is an integer number (551665005156).
Almost surely, 21103330010311 is an apocalyptic number.
1103330010311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1103330010311 is an equidigital number, since it uses as much as digits as its factorization.
1103330010311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 1103330010311 its reverse (1130100333011), we get a palindrome (2233430343322).
The spelling of 1103330010311 in words is "one trillion, one hundred three billion, three hundred thirty million, ten thousand, three hundred eleven".
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