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1103340231421 is a prime number
BaseRepresentation
bin10000000011100100001…
…100111101101011111101
310220110220200022002211121
4100003210030331223331
5121034120044401141
62202511214150541
7142466541140401
oct20034414755375
93813820262747
101103340231421
11395a1888432a
12159a024b2451
1380076b0557c
143b58ad57101
151da78d4e1d1
hex100e433dafd

1103340231421 has 2 divisors, whose sum is σ = 1103340231422. Its totient is φ = 1103340231420.

The previous prime is 1103340231419. The next prime is 1103340231463. The reversal of 1103340231421 is 1241320433011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 790623288900 + 312716942521 = 889170^2 + 559211^2 .

It is a cyclic number.

It is not a de Polignac number, because 1103340231421 - 21 = 1103340231419 is a prime.

It is a super-5 number, since 5×11033402314215 (a number of 61 digits) contains 55555 as substring.

Together with 1103340231419, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1103340231121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551670115710 + 551670115711.

It is an arithmetic number, because the mean of its divisors is an integer number (551670115711).

Almost surely, 21103340231421 is an apocalyptic number.

It is an amenable number.

1103340231421 is a deficient number, since it is larger than the sum of its proper divisors (1).

1103340231421 is an equidigital number, since it uses as much as digits as its factorization.

1103340231421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1103340231421 its reverse (1241320433011), we get a palindrome (2344660664432).

The spelling of 1103340231421 in words is "one trillion, one hundred three billion, three hundred forty million, two hundred thirty-one thousand, four hundred twenty-one".