Base | Representation |
---|---|
bin | 10100100011010010… |
… | …01110111101111111 |
3 | 1001110221100211110122 |
4 | 22101221032331333 |
5 | 140044030041002 |
6 | 5022500525155 |
7 | 540263456633 |
oct | 122151167577 |
9 | 31427324418 |
10 | 11033440127 |
11 | 47520a8966 |
12 | 217b0b07bb |
13 | 106ab353c8 |
14 | 7694d6dc3 |
15 | 4489976a2 |
hex | 291a4ef7f |
11033440127 has 2 divisors, whose sum is σ = 11033440128. Its totient is φ = 11033440126.
The previous prime is 11033440123. The next prime is 11033440139. The reversal of 11033440127 is 72104433011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11033440127 - 22 = 11033440123 is a prime.
It is a super-2 number, since 2×110334401272 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11033440096 and 11033440105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11033440123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5516720063 + 5516720064.
It is an arithmetic number, because the mean of its divisors is an integer number (5516720064).
Almost surely, 211033440127 is an apocalyptic number.
11033440127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11033440127 is an equidigital number, since it uses as much as digits as its factorization.
11033440127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 26.
Adding to 11033440127 its reverse (72104433011), we get a palindrome (83137873138).
The spelling of 11033440127 in words is "eleven billion, thirty-three million, four hundred forty thousand, one hundred twenty-seven".
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