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110341312001 is a prime number
BaseRepresentation
bin110011011000011011…
…0101100111000000001
3101112210212122102102022
41212300312230320001
53301434333441001
6122405021131225
710654234451114
oct1466066547001
9345725572368
10110341312001
1142882880948
12194750b9b15
13a53613077b
1454aa66c57b
152d0c06711b
hex19b0dace01

110341312001 has 2 divisors, whose sum is σ = 110341312002. Its totient is φ = 110341312000.

The previous prime is 110341311979. The next prime is 110341312013. The reversal of 110341312001 is 100213143011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 62050810000 + 48290502001 = 249100^2 + 219751^2 .

It is an emirp because it is prime and its reverse (100213143011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110341312001 is a prime.

It is not a weakly prime, because it can be changed into another prime (110341312801) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55170656000 + 55170656001.

It is an arithmetic number, because the mean of its divisors is an integer number (55170656001).

Almost surely, 2110341312001 is an apocalyptic number.

It is an amenable number.

110341312001 is a deficient number, since it is larger than the sum of its proper divisors (1).

110341312001 is an equidigital number, since it uses as much as digits as its factorization.

110341312001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 110341312001 its reverse (100213143011), we get a palindrome (210554455012).

The spelling of 110341312001 in words is "one hundred ten billion, three hundred forty-one million, three hundred twelve thousand, one".