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110399116181797 is a prime number
BaseRepresentation
bin11001000110100001001100…
…000110101000000100100101
3112110220001102020001112110101
4121012201030012220010211
5103432234342220304142
61030444353120424101
732153034005216242
oct3106411406500445
9473801366045411
10110399116181797
11321a4002a92923
1210470108778031
13497a790790641
141d394ba99a5c9
15cb6b037290b7
hex64684c1a8125

110399116181797 has 2 divisors, whose sum is σ = 110399116181798. Its totient is φ = 110399116181796.

The previous prime is 110399116181719. The next prime is 110399116182023. The reversal of 110399116181797 is 797181611993011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95454443666241 + 14944672515556 = 9770079^2 + 3865834^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110399116181797 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110399116185797) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55199558090898 + 55199558090899.

It is an arithmetic number, because the mean of its divisors is an integer number (55199558090899).

Almost surely, 2110399116181797 is an apocalyptic number.

It is an amenable number.

110399116181797 is a deficient number, since it is larger than the sum of its proper divisors (1).

110399116181797 is an equidigital number, since it uses as much as digits as its factorization.

110399116181797 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5143824, while the sum is 64.

The spelling of 110399116181797 in words is "one hundred ten trillion, three hundred ninety-nine billion, one hundred sixteen million, one hundred eighty-one thousand, seven hundred ninety-seven".