110400000041 has 2 divisors, whose sum is σ = 110400000042. Its totient is φ = 110400000040.

The previous prime is 110399999989. The next prime is 110400000043. The reversal of 110400000041 is 140000004011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 93073806400 + 17326193641 = 305080^2 + 131629^2 .

It is a cyclic number.

It is not a de Polignac number, because 110400000041 - 2¹⁴ = 110399983657 is a prime.

Together with 110400000043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 110399999968 and 110400000031.

It is not a weakly prime, because it can be changed into another prime (110400000043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55200000020 + 55200000021.

It is an arithmetic number, because the mean of its divisors is an integer number (55200000021).

Almost surely, 2^110400000041 is an apocalyptic number.

It is an amenable number.

110400000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

110400000041 is an equidigital number, since it uses as much as digits as its factorization.

110400000041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 11.

Adding to 110400000041 its reverse (140000004011), we get a palindrome (250400004052).

The spelling of 110400000041 in words is "one hundred ten billion, four hundred million, forty-one", and thus it is an aban number.