11040012013 has 4 divisors (see below), whose sum is σ = 11043205308. Its totient is φ = 11036818720.

The previous prime is 11040011971. The next prime is 11040012023. The reversal of 11040012013 is 31021004011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31021004011 = 59 ⋅525779729.

It can be written as a sum of positive squares in 2 ways, for example, as 6489430249 + 4550581764 = 80557^2 + 67458^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11040012013 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11040011984 and 11040012002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11040012023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1591456 + ... + 1598377.

It is an arithmetic number, because the mean of its divisors is an integer number (2760801327).

Almost surely, 2^11040012013 is an apocalyptic number.

It is an amenable number.

11040012013 is a deficient number, since it is larger than the sum of its proper divisors (3193295).

11040012013 is an equidigital number, since it uses as much as digits as its factorization.

11040012013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3193294.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 11040012013 its reverse (31021004011), we get a palindrome (42061016024).

The spelling of 11040012013 in words is "eleven billion, forty million, twelve thousand, thirteen".