Search a number
-
+
11040113 = 72835573
BaseRepresentation
bin101010000111…
…010101110001
3202202220012002
4222013111301
510311240423
61032343345
7162560630
oct52072561
922686162
1011040113
116260667
123844b55
132397116
141675517
15e81228
hexa87571

11040113 has 8 divisors (see below), whose sum is σ = 12664128. Its totient is φ = 9427824.

The previous prime is 11040103. The next prime is 11040119. The reversal of 11040113 is 31104011.

11040113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11040113 - 216 = 10974577 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11040094 and 11040103.

It is not an unprimeable number, because it can be changed into a prime (11040119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 806 + ... + 4767.

It is an arithmetic number, because the mean of its divisors is an integer number (1583016).

Almost surely, 211040113 is an apocalyptic number.

It is an amenable number.

11040113 is a deficient number, since it is larger than the sum of its proper divisors (1624015).

11040113 is an equidigital number, since it uses as much as digits as its factorization.

11040113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5863.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 11040113 is about 3322.6665496255. Note that the first 3 decimals coincide. The cubic root of 11040113 is about 222.6680160057.

Adding to 11040113 its reverse (31104011), we get a palindrome (42144124).

The spelling of 11040113 in words is "eleven million, forty thousand, one hundred thirteen".

Divisors: 1 7 283 1981 5573 39011 1577159 11040113