Base | Representation |
---|---|
bin | 1010000010100111101000… |
… | …0101011111100110010111 |
3 | 1110002102110112121202011012 |
4 | 2200221322011133212113 |
5 | 2421340123214224343 |
6 | 35251431454202435 |
7 | 2216423215305416 |
oct | 240517205374627 |
9 | 43072415552135 |
10 | 11040114211223 |
11 | 35770a4725599 |
12 | 12a3793ab341b |
13 | 621103054706 |
14 | 2a24b6d9347d |
15 | 1422a3201718 |
hex | a0a7a15f997 |
11040114211223 has 2 divisors, whose sum is σ = 11040114211224. Its totient is φ = 11040114211222.
The previous prime is 11040114211201. The next prime is 11040114211229. The reversal of 11040114211223 is 32211241104011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11040114211223 - 234 = 11022934342039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11040114211229) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520057105611 + 5520057105612.
It is an arithmetic number, because the mean of its divisors is an integer number (5520057105612).
Almost surely, 211040114211223 is an apocalyptic number.
11040114211223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11040114211223 is an equidigital number, since it uses as much as digits as its factorization.
11040114211223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 11040114211223 its reverse (32211241104011), we get a palindrome (43251355315234).
The spelling of 11040114211223 in words is "eleven trillion, forty billion, one hundred fourteen million, two hundred eleven thousand, two hundred twenty-three".
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