Base | Representation |
---|---|
bin | 10100100100000110… |
… | …00110100011011111 |
3 | 1001111102010100122011 |
4 | 22102003012203133 |
5 | 140102244041112 |
6 | 5023302132051 |
7 | 540405222265 |
oct | 122203064337 |
9 | 31442110564 |
10 | 11040221407 |
11 | 4755a0a826 |
12 | 2181421027 |
13 | 106c36abb7 |
14 | 76a380435 |
15 | 449386aa7 |
hex | 2920c68df |
11040221407 has 2 divisors, whose sum is σ = 11040221408. Its totient is φ = 11040221406.
The previous prime is 11040221393. The next prime is 11040221411. The reversal of 11040221407 is 70412204011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11040221407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11040221417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520110703 + 5520110704.
It is an arithmetic number, because the mean of its divisors is an integer number (5520110704).
Almost surely, 211040221407 is an apocalyptic number.
11040221407 is a deficient number, since it is larger than the sum of its proper divisors (1).
11040221407 is an equidigital number, since it uses as much as digits as its factorization.
11040221407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 448, while the sum is 22.
Adding to 11040221407 its reverse (70412204011), we get a palindrome (81452425418).
The spelling of 11040221407 in words is "eleven billion, forty million, two hundred twenty-one thousand, four hundred seven".
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