Base | Representation |
---|---|
bin | 10000000100001101011… |
… | …100001110111100100011 |
3 | 10220112200220011200021122 |
4 | 100010031130032330203 |
5 | 121042024204201011 |
6 | 2203104011242455 |
7 | 142522642004342 |
oct | 20041534167443 |
9 | 3815626150248 |
10 | 1104032100131 |
11 | 39624337a554 |
12 | 159b7614942b |
13 | 8015725883c |
14 | 3b614bb5b59 |
15 | 1dab99673db |
hex | 1010d70ef23 |
1104032100131 has 2 divisors, whose sum is σ = 1104032100132. Its totient is φ = 1104032100130.
The previous prime is 1104032100079. The next prime is 1104032100137. The reversal of 1104032100131 is 1310012304011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1104032100131 is a prime.
It is a super-2 number, since 2×11040321001312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1104032100137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552016050065 + 552016050066.
It is an arithmetic number, because the mean of its divisors is an integer number (552016050066).
Almost surely, 21104032100131 is an apocalyptic number.
1104032100131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104032100131 is an equidigital number, since it uses as much as digits as its factorization.
1104032100131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1104032100131 its reverse (1310012304011), we get a palindrome (2414044404142).
The spelling of 1104032100131 in words is "one trillion, one hundred four billion, thirty-two million, one hundred thousand, one hundred thirty-one".
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