Base | Representation |
---|---|
bin | 10100100100000111… |
… | …11001011111110011 |
3 | 1001111102111221212022 |
4 | 22102003321133303 |
5 | 140102322230232 |
6 | 5023310422055 |
7 | 540410051522 |
oct | 122203713763 |
9 | 31442457768 |
10 | 11040430067 |
11 | 4756042577 |
12 | 218150192b |
13 | 106c411b74 |
14 | 76a3d64b9 |
15 | 4493c8812 |
hex | 2920f97f3 |
11040430067 has 2 divisors, whose sum is σ = 11040430068. Its totient is φ = 11040430066.
The previous prime is 11040429989. The next prime is 11040430069. The reversal of 11040430067 is 76003404011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11040430067 is a prime.
It is a super-3 number, since 3×110404300673 (a number of 31 digits) contains 333 as substring.
Together with 11040430069, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11040430069) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520215033 + 5520215034.
It is an arithmetic number, because the mean of its divisors is an integer number (5520215034).
Almost surely, 211040430067 is an apocalyptic number.
11040430067 is a deficient number, since it is larger than the sum of its proper divisors (1).
11040430067 is an equidigital number, since it uses as much as digits as its factorization.
11040430067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 26.
Adding to 11040430067 its reverse (76003404011), we get a palindrome (87043834078).
The spelling of 11040430067 in words is "eleven billion, forty million, four hundred thirty thousand, sixty-seven".
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