110404321202131 has 8 divisors (see below), whose sum is σ = 120449812417200. Its totient is φ = 100360285777440.

The previous prime is 110404321202113. The next prime is 110404321202243. The reversal of 110404321202131 is 131202123404011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 110404321202131 - 2⁹ = 110404321201619 is a prime.

It is a super-2 number, since 2×110404321202131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110404321202096 and 110404321202105.

It is not an unprimeable number, because it can be changed into a prime (110404321202431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 363789016 + ... + 364092373.

It is an arithmetic number, because the mean of its divisors is an integer number (15056226552150).

Almost surely, 2^{110404321202131} is an apocalyptic number.

110404321202131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

110404321202131 is a deficient number, since it is larger than the sum of its proper divisors (10045491215069).

110404321202131 is a wasteful number, since it uses less digits than its factorization.

110404321202131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 727895189.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 110404321202131 its reverse (131202123404011), we get a palindrome (241606444606142).

The spelling of 110404321202131 in words is "one hundred ten trillion, four hundred four billion, three hundred twenty-one million, two hundred two thousand, one hundred thirty-one".