Base | Representation |
---|---|
bin | 10000000100010001101… |
… | …011001000011011001111 |
3 | 10220112212211210120121111 |
4 | 100010101223020123033 |
5 | 121042200344130242 |
6 | 2203115025312451 |
7 | 142524463424224 |
oct | 20042153103317 |
9 | 3815784716544 |
10 | 1104103114447 |
11 | 39627a473673 |
12 | 159b95a95727 |
13 | 80168b90c48 |
14 | 3b6203bd94b |
15 | 1dac0ce3817 |
hex | 10111ac86cf |
1104103114447 has 2 divisors, whose sum is σ = 1104103114448. Its totient is φ = 1104103114446.
The previous prime is 1104103114393. The next prime is 1104103114483. The reversal of 1104103114447 is 7444113014011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1104103114447 - 219 = 1104102590159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1104103114487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552051557223 + 552051557224.
It is an arithmetic number, because the mean of its divisors is an integer number (552051557224).
Almost surely, 21104103114447 is an apocalyptic number.
1104103114447 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104103114447 is an equidigital number, since it uses as much as digits as its factorization.
1104103114447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5376, while the sum is 31.
Adding to 1104103114447 its reverse (7444113014011), we get a palindrome (8548216128458).
The spelling of 1104103114447 in words is "one trillion, one hundred four billion, one hundred three million, one hundred fourteen thousand, four hundred forty-seven".
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