11041433441 has 4 divisors (see below), whose sum is σ = 11055082500. Its totient is φ = 11027784384.

The previous prime is 11041433419. The next prime is 11041433483. The reversal of 11041433441 is 14433414011.

It is a happy number.

11041433441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 14433414011 = 19 ⋅759653369.

It can be written as a sum of positive squares in 2 ways, for example, as 10589233216 + 452200225 = 102904^2 + 21265^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11041433441 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11041433441.

It is not an unprimeable number, because it can be changed into a prime (11041433141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6823316 + ... + 6824933.

It is an arithmetic number, because the mean of its divisors is an integer number (2763770625).

Almost surely, 2^11041433441 is an apocalyptic number.

It is an amenable number.

11041433441 is a deficient number, since it is larger than the sum of its proper divisors (13649059).

11041433441 is an equidigital number, since it uses as much as digits as its factorization.

11041433441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13649058.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 11041433441 its reverse (14433414011), we get a palindrome (25474847452).

The spelling of 11041433441 in words is "eleven billion, forty-one million, four hundred thirty-three thousand, four hundred forty-one".